If the concentration of glucose in blood is 0.9g/l what will be the molarity of glucose in blood *

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Text Solution

5M50M0.005M0.5M

Answer : C

Solution : In the given question 0.9 `gL^(-1)` means that 1000(mL) solution contains 0.9g of glucose. <br> `therefore` Number of moles `=0.9g "glucose"=(0.9)/(180)` mol glucose <br> `=5xx10^(-3)` mol glucose <br> (where , molecular mass of glucose `(C_(6)H_(12)O_(6))=12xx6+12xx1+6xx16=180u`) <br> i.e. L solution contains 0.05 mole glucose or the molarity of glucose is 0.005M.

If the concentration of glucose \[\ce{(C6H12O6)}\] in blood is 0.9 g L–1, what will be the molarity of glucose in blood?

0.005 M

Explanation:

Molar mass of glucose \[\ce{(C6H12O6)}\]

= 12 × 6 + 1 × 12 + 16 × 6 = 180

Molarity = `("conc. in gL"^-1)/"Molar mass" = (0.90  "gL"^-1)/(180  "g mol"^-1)` = 0.005 M

Concept: Stoichiometry and Stoichiometric Calculations - Reactions in Solutions

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