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Solution for 5x^2=-8-5 equation:
Simplifying 5x2 = -8 + -5 Combine like terms: -8 + -5 = -13 5x2 = -13 Solving 5x2 = -13 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Divide each side by '5'. x2 = -2.6 Simplifying x2 = -2.6 Reorder the terms: 2.6 + x2 = -2.6 + 2.6 Combine like terms: -2.6 + 2.6 = 0.0 2.6 + x2 = 0.0 The solution to this equation could not be determined.
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Step by step solution :
Step 1 :
Equation at the end of step 1 :
(5x2 - 8x) + 5 = 0Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 5x2-8x+5
The first term is, 5x2 its coefficient is
5 .
The middle term is, -8x its coefficient is -8 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 5 • 5 = 25
Step-2 : Find two factors of 25 whose sum equals the coefficient of the middle term, which is -8 .
-25 | + | -1 | = | -26 | ||
-5 | + | -5 | = | -10 | ||
-1 | + | -25 | = | -26 | ||
1 | + | 25 | = | 26 | ||
5 | + | 5 | = | 10 | ||
25 | + | 1 | = | 26 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
5x2 - 8x + 5 = 0Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = 5x2-8x+5Parabolas have a highest or a
lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 5 , is positive (greater than zero). Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would,
for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions. Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to
find the coordinates of the vertex. For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 0.8000 Plugging into the parabola formula 0.8000 for x we can calculate the y -coordinate :
y
= 5.0 * 0.80 * 0.80 - 8.0 * 0.80 + 5.0
or y = 1.800
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 5x2-8x+5
Axis of Symmetry (dashed) {x}={ 0.80}
Vertex at {x,y} = { 0.80, 1.80}
Function has no real roots
Solve Quadratic Equation by Completing The Square
3.2 Solving 5x2-8x+5 = 0 by Completing The Square .Divide both sides of the equation by 5 to have 1 as the coefficient of the first term :
x2-(8/5)x+1 = 0
Subtract 1 from both side of the equation :
x2-(8/5)x
= -1
Now the clever bit: Take the coefficient of x , which is 8/5 , divide by two, giving 4/5 , and finally square it giving 16/25
Add 16/25 to both sides of the equation :
On the right hand side we have :
-1 + 16/25 or,
(-1/1)+(16/25)
The common denominator of the two fractions is 25 Adding (-25/25)+(16/25) gives -9/25
So adding to both sides we finally get :
x2-(8/5)x+(16/25) = -9/25
Adding 16/25 has completed the left hand side into a perfect square :
x2-(8/5)x+(16/25) =
(x-(4/5)) • (x-(4/5)) =
(x-(4/5))2
Things which are equal to the same thing are also equal to one another. Since
x2-(8/5)x+(16/25) = -9/25 and
x2-(8/5)x+(16/25) = (x-(4/5))2
then, according to the law of transitivity,
(x-(4/5))2 = -9/25
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(4/5))2 is
(x-(4/5))2/2 =
(x-(4/5))1 =
x-(4/5)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x-(4/5) =
√ -9/25
Add 4/5 to both sides to obtain:
x = 4/5 + √ -9/25
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square
roots of -1
Since a square root has two values, one positive and the other negative
x2 - (8/5)x + 1 = 0
has two solutions:
x = 4/5 + √ 9/25 • i
or
x = 4/5 - √ 9/25 • i
Note that √ 9/25 can be written
as
√ 9 / √ 25 which is 3 / 5
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 5x2-8x+5 = 0 by the Quadratic Formula .According to the Quadratic Formula, x , the
solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ±
√ B2-4AC
x = ————————
2A In our case, A = 5
B = -8
C =
5 Accordingly, B2 - 4AC =
64 - 100 =
-36Applying the quadratic formula :
8
± √ -36
x = —————
10In the set of real numbers, negative numbers do not have square roots. A new set of numbers, called complex, was invented so that negative numbers would have a square root. These numbers are written (a+b*i)
Both i and -i are the square roots of minus 1
Accordingly,√ -36 =
√ 36 • (-1) =
√ 36 • √ -1 =
± √
36 • i
Can √ 36 be simplified ?
Yes! The prime factorization of 36 is
2•2•3•3
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second
root).
√ 36 = √ 2•2•3•3 =2•3•√ 1 =
± 6 • √ 1 =
± 6
So now we
are looking at:
x = ( 8 ± 6i ) / 10
Two imaginary solutions :
x =(8-√-36)/10=(4-3i)/5= 0.8000-0.6000i
Two solutions were found :
- x =(8-√-36)/10=(4-3i)/5= 0.8000-0.6000i
- x =(8+√-36)/10=(4+3i)/5= 0.8000+0.6000i