Consider the function f : N → N given by f (0) 0 and f (n + 1) f (n) + 2n + 1. Find f (6).36A simple graph has no loops nor multiple edges. f : N → N, arecursivedefinition consists of aninitial conditiontogether with arecurrence relationTherangeis a subset of the codomain. It is the set of all elements which are assigned toat least one element of the domain by the function. That is, the range is the set of alloutputs.Abijectionis a function which is both an injection and surjection. In other words, if everyelement of the codomain is the image of exactly one element from the domain
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Transcribed Image Text:Consider the function f : N → N given by f(0) = 0 and f(n + 1) = f(n) + 2n + 1. Find f(6).
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