Which system of equations could be graphed to solve the equation below? log _0.5x=log _32+x y_1=frac log 0.5x,y_2=frac log 32+x y_1=frac log xlog 0.5,y_2=frac log 2+xlog 3 y_1=frac log 0.5log 3,y_2=frac log xlog 2+x y_1=frac log xlog 0.5,y_2=frac log 2log 3+x
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Gauthmathier2053
Grade 11 · 2021-10-14
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Which system of equations could be graphed to solve the equation below?
Which system of equations could be graphed to solv - Gauthmath
y_{1}=\frac {\log 0.5}{x},
y_{2}=\frac {\log 3}{2+x}
y_{1}=\frac {\log x}{\log 0.5},
y_{2}=\frac {\log 2+x}{\log 3}
y_{1}=\frac {\log 0.5}{\log 3},
y_{2}=\frac {\log x}{\log 2+x}
y_{1}=\frac {\log x}{\log 0.5},
y_{2}=\frac {\log 2}{\log 3}+x
Gauthmathier6332
Grade 11 · 2021-10-14
Answer
Explanation
Solve the equations:
x = 0.467140821018068
Answer:
x = 0.467140821018068
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Video Transcript
So in order to solve this answer on my calculator, what I could do is I can set up two equations. I could say, okay, Y sub one equals my left side, log base 0.5 of X. And Y. Sub two equals my right side. Log base three of two plus X. Where plus X. Is outside of the log rhythm. Okay so how can I rewrite these? Well log base 0.5 doesn't exist in my calculator but I can write log base 10 of X. Over log base 10 of 0.5. Remember um when there's no base it's assumed that this is log base 0.5. Then my other one I could write this as this can transform as log base two. All over a log base three. And then I'm still adding X. Outside of this function because the plus X is not inside the logarithms. So Which of these would be true? Well this would be the 4th choice because this plus sex. If it was inside the log rhythm it had parentheses around it. But since it doesn't Log Base two over log base three plus X. Outside of it.
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- Which system of equations could be graphed to solve the equation below? logo.sxlog32+x log0.5 log3 .y2 2+X O Y1= log2+x logx y1 Tog0.52log3 log0.5 Y1Tog32 Tog2+x logx log2 +X logx y1 Tog0.52 Tog3
Question: Which system of equations could be graphed to solve the equation below? logo.sxlog32+x log0.5 log3 .y2 2+X O Y1= log2+x logx y1 Tog0.52log3 log0.5 Y1Tog32 Tog2+x logx log2 +X logx y1 Tog0.52 Tog3
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