What is the area swept by the minute hand in 5 minutes if the length of the minute hand of a clock is 40 cm?

Solution:

We use the formula for the area of the circle to find the area swept by the minute hand.

We know that the minute hand completes one rotation in 1 hour or 60 minutes.

Therefore, area swept by the minute hand in 60 minutes = Area of the circle with radius equal to the length of the minute hand = πr2

Using unitary method, we get

Area swept by minute hand in 1 minute = πr2/60

Thus, area swept by minute hand in 5 minutes = (πr2/60) × 5 = πr2/12

Length of the minute hand (r) = 14 cm

It is known that the minute hand completes one rotation in 1 hour or 60 minutes

Therefore, the area swept by the minute hand in 60 minutes = πr2

Therefore, the area swept by the minute hand in 5 minutes = 5/60 × πr2 ⇒ 1/12 πr2

= 1/12 × 22/7 × 14 × 14 cm2

= 154/3 cm2

☛ Check: NCERT Solutions Class 10 Maths Chapter 12

Video Solution:

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.2 Question 3

Summary:

The area swept in 5 minutes by the minute hand of length 14 cm of a clock is 154/3 cm2.

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