Object distance (u) = - 20 m ( negative, due to sign convention)Focal length (f) = -10 m ( negative, due to sign convention)Image distance = ?
From the mirror formula, we know that:
`1/v+1/u=1/f`
or `1/v+1/-20=(-1)/10`
or `1/v-_20^1=_10^-1`
or `1/v=(-1)/10+1/20`
or `1/v=-1/20orv=-20m`
Here, the negative sign means that the image is formed on the left side of the mirror. Thus, it is a real and inverted image, formed at a distance of 20 m from the mirror.
CBSE 10 - Physics
Asked by topperlearningforcontent | 02 Feb, 2022, 03:32: PM
Find the size, nature and position of image formed when an object of size 1 cm is placed at a distance of 15 cm from a concave mirror of focal length 10cm
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a Virtual, not magnified b Virtual, magnified c Real, not magnified d Real, magnified
Answer : B
Solution : When the object is kept in between concave mirror <br> and its focal length, then nature of image would be <br> virtual and magnigied.