If two dice are rolled, what is the probability that the sum is greater than 3 but less than 11

All possible results when throwing 2 dices ( 2-3 combination IS THE SAME as 3-2, you know it if you ever played dice, I don't know what are the probability purposes Casey is talking about ): (1,1) (1,2) (2,2) (1,3) (2,3) (3,3) (1,4) (2,4) (3,4) (4,4) (1,5) (2,5) (3,5) (4,5) (5,5) (1,6) (2,6) (3,6) (4,6) (5,6) (6,6) so there are 21 combinations, only (5,6) and (6,6) are >=11, so the answer is: 2/21=9.52%

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Do you know how to calculate this probability? The total number of possible outcome is $12$. Numbers that is greater than $3$ is $4,5,6$. For 2 dices that would be $6/12$ or $1/2$.

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