Silver nitrate and potassium iodide

Answer

Índice Show

The correct option is B AgI/I−When silver nitrate is added to excess KI, AgI gets precipitated. AgNO3(aq)+KI(aq)→AgI(s)↓+AgNO3(aq) (adsbygoogle = window.adsbygoogle || []).push({}); The precipitated silver iodide adsorbs iodide ions (I−) from the dispersion medium and negatively charged colloidal sol is formed AgI/I−. Hence, option (d) is correct.
What happens when silver nitrate reacts with potassium iodide?
Does AgNO3 and KI form A precipitate?
What type of reaction is AgNO3 KI → KNO3 AgI?
What type of reaction is silver nitrate and potassium iodide?

Verified

Hint:The colloidal sols are divided into positively charged sol and negatively charged sol. The positively charged sol are metal hydroxides and the negative charged sols are of metal sulphide.

Complete answer:
When a dilute solution of potassium iodide(KI) is added to dilute solution of silver nitrate, a positive charge sol to silver iodide (AgI) is generated. This formation of positive charge sol is because of absorption of silver ions($A{g^ + }$).from the dispersion medium on the precipitate formed by silver iodide (AgI).
The reaction of silver nitrate with potassium iodide is shown below.
$AgN{O_3}(excess) + KI \to AgI\xrightarrow{{AgN{O_3}}}AgI/A{g^ + }$
When a dilute solution of silver nitrate (AgI) is added to excess dilute solution of potassium iodide, silver iodide with negative charged sol is generated. This formation of negative charged sol is due to the absorption of iodide ion (${I^ - }$) from the dispersion medium on the precipitate formed by the silver iodide.
$AgN{O_3} + KI(excess) \to AgI\xrightarrow{{AgN{O_3}}}AgI/{I^ - }$
When silver nitrate is reacted with excess potassium iodide, the colloidal particles formed get released towards the anode.
Thus, when excess of $AgN{O_3}$ is treated with KI solution, AgI forms a positively charged sol.
Therefore, the correct option is (A).

Note:
Make sure about the amount of silver nitrate used. The slight difference in the amount will affect the formation of sol. The classification of colloidal sol is dependent on the nature of the charge which is present in the particles of the dispersed phase.

When balancing chemical equations our goal is to have the same number of each type of atom on both sides of the equation.

Only change the coefficients (these are the numbers in front substances).

Never change the subscripts (the small numbers after elements).

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Solution

The correct option is B AgI/I−When silver nitrate is added to excess KI, AgI gets precipitated. AgNO3(aq)+KI(aq)→AgI(s)↓+AgNO3(aq) (adsbygoogle = window.adsbygoogle || []).push({}); The precipitated silver iodide adsorbs iodide ions (I−) from the dispersion medium and negatively charged colloidal sol is formed AgI/I−. Hence, option (d) is correct.

What happens when silver nitrate reacts with potassium iodide?

a) When silver nitrate solution is added to potassium iodide solution. the precipitated silver iodide adsorbs iodide ions from the dispersion medium and negatively charged colloidal solution results.

Does AgNO3 and KI form A precipitate?

yellow ppt. Referring to our original table (previous page), we see that the formation of a yellow precipitate on mixing 1 and 2 indicates that these are AgNO3 and KI.

What type of reaction is AgNO3 KI → KNO3 AgI?

Type of Chemical Reaction: For this reaction we have a double replacement reaction.

What type of reaction is silver nitrate and potassium iodide?

Answer. They used to call this type of reaction a double replacement reaction. If this was an aqueous reaction, silver iodide would form as precipitate.

Silver nitrate and potassium iodide