Prove the following: Find the angle of elevation of the sun when the shadow of a pole h metres high is `sqrt(3)` h metres long. Let the angle of elevation of the Sun is θ. Given, height of pole = h m Now, In ∆ABC `tan theta = (AC)/(BC) = h/(sqrt(3)h)` ⇒ `tan theta = sqrt(1)/3` ⇒ `tan 30^circ` ⇒ `theta = 30^circ` Hence, the angle of elevation of the Sun is 30°. Concept: Proof of Existence Is there an error in this question or solution? Text Solution `30^@``45^@``60^@``90^@` Answer : A Solution : Let the angle of elevation of the Sun is `theta`. <br> Given, height of pole =h <br> Now, in `DeltaABC`, <br> `tantheta= (AB)/(BC) = h/(sqrt(3)h)` <br> `tantheta=1/sqrt(3)= tan30^(@) rArr theta = 30^(@)` <br> Hence, the angle of elevation of the Sun is `30^(@)`. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_X_C08_S01_035_S01.png" width="80%"> Open in App Suggest Corrections 1 |