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I did this $^{25}C_{4}-^{7}C_{4}=12615$ quadrilaterals. But the book is giving answer $^{25}C_{4}-^{7}C_{4}-^{7}C_{3}\times ^{18}C_{1}=11985$ quadrilaterals.. I don't know what is the correct idea . I look for a short and simple way. I have studied maths up to $12$th grade.
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