What quantity of pure acid must be added to 600mL of a 45% acid solution to produce a 70% acid solution x + .45(600) = .70(600+x) x + 270 = 420+.70x .30x + 270 = 420 .30x = 150 x = 500 mL
Allie H. 1 Expert Answer
Adam K. answered • 02/05/16 Central Catholic Math Teacher/Department Head
So 1x + .5(300) = .6(x + 300) This formula is in other words: 100% of x ml are added to 50% of 300ml to get 60% of the total (x+300) Solving this gets you x = 75ml
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You can put this solution on YOUR website! What quantity of pure acid must be added to 400 mL of a 25% acid solution to produce a 70% acid solution? . Let x = amount (mL) of pure acid to add then x + .25(400) = .70(400+x) x + 100 = 280+.70x .30x + 100 = 280 .30x = 180 x = 600 mL |
What amount of pure acid must be added to 400 ml of a 35% acid solution to produce a 60% acid solution?
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