Object distance (u) = - 20 m ( negative, due to sign convention)Focal length (f) = -10 m ( negative, due to sign convention)Image distance = ? From the mirror formula, we know that: `1/v+1/u=1/f` or `1/v+1/-20=(-1)/10` or `1/v-_20^1=_10^-1` or `1/v=(-1)/10+1/20` or `1/v=-1/20orv=-20m` Here, the negative sign means that the image is formed on the left side of the mirror. Thus, it is a real and inverted image, formed at a distance of 20 m from the mirror.
CBSE 10 - Physics Asked by topperlearningforcontent | 02 Feb, 2022, 03:32: PM ANSWERED BY EXPERTOpen in App Suggest Corrections 22 Text Solution a Virtual, not magnified b Virtual, magnified c Real, not magnified d Real, magnified Answer : B Solution : When the object is kept in between concave mirror <br> and its focal length, then nature of image would be <br> virtual and magnigied. |