What is the total number of moles of NaCl formed when 2 moles of Na2CrO4 react completely

Chemistry, 28.07.2019 07:00, nesa10

Answers

The correct answer was given: xXFLUFFYXx

Na2CrO4  react  with  PbCl2  to  form  PbcrO4  +2 NaClthe  total  number  of  moles  of  nacl  when 2 Na2crO4  react   completely    is  calculated  by  use  of  reacting  ration  between   Na2CrO4  and  NaCl  which  is  1:2  

therefore  the  moles  of   Nacl  is =   2  x2   =  4  moles

The correct answer was given: Tiredd7838

The balanced chemical equation for the above reaction is as follows;2Na₂CrO₄ + 2HCl ---> Na₂Cr₂O₇ + 2NaCl + H₂Ostoichiometry of Na₂CrO₄ to NaCl is 2:2the amount of moles of Na₂CrO₄ reacted is equal to the number of moles of NaCl produced.We are told that Na₂CrO₄ reacts completely, this means that this is the limiting reactant , amount of product forms depends on amount of limiting reactant present.When 2 mol of Na₂CrO₄ is used up , according to stoichiometry number of NaCl moles formed are equal to that.

Therefore number of NaCl moles formed - 2 mol

The correct answer was given: Brain

i think so it’s will be b yes i believe its

The correct answer was given: Brain

[tex]\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}[/tex]

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

[tex]\frac{103}{40}x=\frac{103}{40}zr[/tex]

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