The first line in Paschen series corresponds transition from n = 4 to n = 3, so wavelength is given as, 1λ2= RH 1n12-1n221λ2= RH 132-1521λ2=RH 19-1251λ2=RH 16225λ2 = 22516RHNow, ratio of two wavelength is given as,λ1λ2 = 1447RH×16RH225 = 256175 or 1.46 Get Instant Solutions When in doubt download our app. Now available Google Play Store- Doubts App Download NowYour tool of choice here will be the Rydberg equation, which tells you the wavelength, #lamda#, of the photon emitted by an electron that makes a #n_i -> n_f# transition in a hydrogen atom.
Here
Now, the Paschen series is characterized by #n_f = 3#. The first transition in the Paschen series corresponds to
In this transition, the electron drops from the fourth energy level to the third energy level. You will have
The second transition in the Paschen series corresponds to
This time, you have
Now, to get the ratio of the first line to that of the second line, you need to divide the second equation by the first one.
This will be equivalent to
Therefore, you can say that you have
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