Vapour pressure of pure water at 298 K is 23.8 mm. 50 g of urea (NH2CONH2) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.
Vapoure pressure of pure water (solvent) at 298 K, p0 = 23.8 mmVapour pressure of solution, p = ?Mass of solvent ,W = 850 gMass of solute,M = 50 g Mol. mass of water (H2O), M = 18 g mol–1 = 60 g mol–1 According to Raoult's law, p0-pp0=ωMWm p=p0-w×Mm×W×p° p=23.8-50×1860×850 =23.8-0.017=23.78 Hence, 23.78 mm Hg. Ans. Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! |