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STEPS:
Proof of Construction: PA = AB = BC = CD = DE since these lengths represent copies of the radius of circle O. But how do we know for sure that the last length, EP, coincided exactly with point P? Is EP actually the same length as the other copied radii? ΔDOE is an equilateral triangle since it has 3 sides of equal length (DO and OE are radii lengths and DE is a copy of this radii length). In similar fashion, ΔCOD, ΔBOC. ΔAOB and ΔPOA are also equilateral triangles. Since the interior angles of an equilateral triangle each contain 60º, m∠COD = m∠BOC = m∠AOB = m∠POA = m∠DOE = 60º. Since all of the central angles (surrounding a point) must add to 360º, we know the m∠POE = 60º (360º - 300º = 60º). Since we have ΔDOE ΔDOE by SAS. By CPCTC, and we know that the last copy of the radii coincides with point P making the hexagon truly inscribed. Hexagon PABCDE has all vertices on circle O, has congruent interior angles (each equal 120º) and has all sides congruent. PABCDE is an inscribed regular hexagon by definition.
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