Solution: Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event. For an experiment having n number of outcomes, the number of favorable outcomes can be denoted by : Let ‘x’ be the number on the first dice ‘Y’ be the number on second dice First dice showing odd number = {1,3,5} Second dice also has odd number = {1,3,5} The probability that the first dice shows an odd number = 3/6. The probability that the second dice shows an odd number = 3/6. The possible results are (1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5). The probability that both dice show an odd number is (3/6) × (3/6) = 9/36 = 1/4 Therefore, the probability of getting an odd number in both dice is 1/4. Summary: If you roll two fair six-sided dice, the probability that both dice show an odd number is 1/4. No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections 0
To answer the question: 5/11 and 6/11. The possible sum of rolling two dice is 2,3,4.....,12. Total 11 possibilities, 5 odds and 6 evens. Now, the probability of each sum value is not alike for all possibilities. For eg., sum 2 - (1,1) - prob: 1/36 Sum 3 - (1,2),(2,1) - prob: 2/36 . . Sum 10- (5,5),(4,6),(6,4) prob:3/36 Sum 12-(6,6) prob:1/36 Hence, had it been the sum probabilities are same then 5/11 and 6/11 are valid. But since the probabilities are different, actual probabilities of odds is 18/36 or 1/2. |