In a non leap year what is the probability of 53 Sundays

getcalc.com's Probability calculator to find what is the probability of 53 Sundays in a non-leap year. The ratio of expected event to all the possible events of a sample space for 1 odd day to be Sunday is the probability of getting 53 Sundays for a non-leap year.
P(A) = 1/7 = 0.14

Users may refer the below detailed information to learn how to find the probability of 53 Sundays in an ordinary year. The total number of weeks in a non-leap year {365 days = 52 (1/7)} is 52 weeks and one odd day. Since, finding the probability for an odd day to be Sunday is enough to find the probability of getting 53 Sundays in an ordinary year of a Gregorian calendar.

Workout
step 1 Possible events for 1 odd day The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.

step 2 Probability of 1 Odd day to be Sunday :

{Sunday}/{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

0.14 or 1/7 is probability for 53 Sundays in a non-leap year.

A non leap year

TO FIND: Probability that a non leap year has 53 Sundays.

Total number of days in non leap year is 365days

Hence number of weeks in a non leap year is  `365/7=52`  weeks and 1 day

In a non leap year we have 52 complete weeks and 1 day which can be any day of the week e.g. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday To make 53 Sundays the additional day should be Sunday Hence total number of days is 7

Favorable day i.e. Sunday is 1 

`"We know that PROBABILITY" = "Number of favourable event" /"Total number of event"`

Hence probability that a non leap year has 53 Sundays is `1/7` 

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