Two cards are drawn from a deck of 52 cards. what is the probability that they are both kings

Text Solution

Answer : `1/221`

Solution : Probability of first card to be a king, `P(A)=4//52` and probability of secod to be a king, `P(B)=3//51.` Hence, orequired probability is <br> `P(AnnB)=4/52xx3/51=1/121`

$\begingroup$

Four cards are randomly selected from a pack of 52 cards. If the first two cards are kings, what is the probability that the third card is a king?

The given answer is 2/50.

I was thinking 4 cards can be selected in 52C4 ways, out of which first three kings can be selected in 4P3 ways i.e. 24 ways and last 1 card can be choose by 49 ways. Hence result should be equal to (24*49)/(52C4)

Where am I going wrong?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!