Answered by Guest on 2019-04-08 10:15:08 | Votes 19 | # Solution Total amount under compound interest = $12000 (1 + \frac{9}{100})^2$ = $12000 \times 1.09 \times 1.09$ = $14257.2$ $\therefore$ Compound Interest = 14257.2 - 12000 = Rs. 2,257.2 Join Telegram Group
Answered by Guest on 2019-04-29 09:22:48 | Votes 2 | # Solution Total amount under compound interest = $12000 (1 + \frac{9}{100})^2$ = $12000 \times 1.09 \times 1.09$ = $14257.2$ $\therefore$ Compound Interest = 14257.2 - 12000 = Rs. 2,257.2
15 Questions 15 Marks 12 Mins
Let P = Principal, R = rate % per annum, Time = n years. When interest is compound annually, Amount = P(1 + R/100)n Given, P = Rs.12000 and n = 2 years and R = 5% Amount = = 12000[1 + 5/100]2 = 12000[1 + 0.05]2 = 12000 × 1.05 × 1.05 = 13230 Compound interest = amount - P Compound interest = 13230 - 12000 = 1230 ∴ Compound Interest is Rs. 1230.India’s #1 Learning Platform Start Complete Exam Preparation
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