What is the maximum number of orbitals that can be identified with the following quantum numbers n 4 L 2?

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

We know Energy of the incident radiation = Work function + KE of photoelectron

Work function = Energy of the incident

radiation - KE of photoelectron ..(1).Now energy of the incident radiation (E) = hv

..(2)

Substituting the values in eq. (2), we have

Energy of incident radiation

The potential applied gives the kinetic energy to the electron. Hence, the kinetic energy of the electron = 4.4 eV.Substituting the values in eq. (1), we have Work function = 4.83 eV - 0.35 eV = 4.48 eV

Correct Answer: (Option A – 1)

Explanation:

n = 3, ℓ = 1, m = 0

Orbital is 3pz

So only one orbital can be identified with these quantum numbers.

In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.

Text Solution

1234

Answer : A

Solution : n=3, l=1, so, the resultant subhsell is 3p. <br> Number of orbitals having n=3, l=1 & `m_(l)=0` is one.

Text Solution

1234

Answer : A

Solution : (a) The value of n=3 and l=1 suggests that it is a 3p-orbital while the value f `m_(l)=0` [magnetic quantum number ] shows that the given 3p-orbital is `3p_(z)` in nature. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_31Y_NEET_CHM_C02_E01_007_S01.png" width="80%"> <br> Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. `3p_(z)`.

What is the maximum number of orbitals that can be identified with the following quantum numbers?n=3,l=+1,ml =0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!