Text Solution `156200J``156250J``156275J``156300J` Answer : B Solution : Mass of the car, `m =1500 kg`, <br> initial velocity of car, `u = 30 km h^(-1)` <br> `=(30xx1000 m)/((60 xx 60 s)` <br> `=25//3 ms^(-1)` <br> Similarly, the final velocity of the car, <br> `v = 60 km h^(-1)` <br> `=50//3 ms^(-1)` <br> Therefore, the initial kinetic energy of the car, <br> `E_(kt) = (1)/(2) m u^(2)` <br> `=(1)/(2)xx1500 kg xx (25//3 ms^(-1))^(2)` <br> = 156250/3 J <br> The final kinetic energy of the car, <br> `E_(kf)=(1)/(2) xx1500 kg xx(50//3 ms^(-1))^(2)` <br> = 625000/3 J. m <br> Thus, the work done = Change in kinetic energy <br> `=E_(kf) - E_(kt)` <br> = 156250 J. Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now
Given, Mass of the car, m = 1500 kg Initial velocity of the car, u = 30 km/h = $\frac{30\times 1000m}{3600s}=\frac{25}{3}m/s$ [converted km/h to m/s] Final velocity of the car, v = 60 km/h = $\frac{60\times 1000m}{3600s}=\frac{50}{3}m/s$ [converted km/h to m/s] To find = Work done (W) Solution: According to the Work-Energy theorem or the relation between Kinetic energy and Work done - the work done on an object is the change in its kinetic energy. So, Work done on the car = Change in the kinetic energy (K.E) of the car = $Final\ K.E-Initial\ K.E$ $Work\ done, \ W =\frac{1}{2}m{v}^{2}-\frac{1}{2}m{u}^{2}$ $[\because K.E=\frac{1}{m}{v}^{2}, \ where, \ mass\ of\ the\ body=m,\ and\ the\ velocity\ with\ which\ the\ body\ is\ travelling=v]$ $W=\frac{1}{2}m[{v}^{2}-{u}^{2}]$ $[taking\ out\ common]$ Now, substituting the values- $W=\frac{1}{2}\times 1500[(\frac{50}{3}{)}^{2}-(\frac{25}{3}{)}^{2}]$ $W=\frac{1}{2}\times 1500[(\frac{50}{3}+\frac{25}{3})(\frac{50}{3}-\frac{25}{3})]$ $[\because ({a}^{2}-{b}^{2})=(a+b)(a-b)]$ $W=\frac{1}{2}\times 1500\times \frac{75}{3}\times \frac{25}{3}$ $W=156250J$ Hence, the work to be done to increase the velocity of a car from 30km/h to 60km/h is 156250 joule, if the mass of the car is 1500 kg. |