When 1 mole of ammonia and 1 mole of O2 are mixed then the number of moles of NO formed will be?

1 mole of $H_{2}O$ is produced

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Oxygen is completely consumed

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Text Solution

1.0 mole of `H_(2)O` is produced1.0 mole of NO will be producedall the oxygen will be consumedall the ammonia will be consumed

Answer : C

Solution : `underset(" 4 mol")(4NH_(3)(g))+underset("5 mol")(5O_(2)(g))tounderset("4 mol")(4NO(g))+underset("6 mol")(6H_(2)O(1))` <br> According to equation , <br> 5 moles of `O_(2)` required = 4 moles of ` NH_(3)` <br> 1 mole of `O_(2)` requires `=(4)/(5)=0.8` mole of `NH_(3)` While 1 mole of `NH_(3)` requires `=(5)/(4) = 1.25 " moles of " O_(2)` <br> As there is 1 mole of `NH_(3)` and 1 mole of `O_(2)` , so all the oxygen will be consumed .